Take a look at the attachment to see the solution.
A = future value
P = principal (P = 12,000)
r = interest rate (r=6)
n = time periods (n=12)
Answer:



Therefore,
Option (A) is false
Option (B) is false
Option (C) is false
Step-by-step explanation:
Considering the graph
Given the vertices of the segment AB
Finding the length of AB using the formula







units
Given the vertices of the segment JK
From the graph, it is clear that the length of JK = 5 units
so
units
Given the vertices of the segment GH
Finding the length of GH using the formula





![\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%5C%3A%7D%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200)
units
Thus, from the calculations, it is clear that:
Thus,



Therefore,
Option (A) is false
Option (B) is false
Option (C) is false
Dude tbh, I’m on the same problem as you and I need help with the answer.!!
X=52 (vertically opposite angles)
<span>3t>5t+12
Subtract 5t from both sides to get the variable on only one side.
-2t>12
Divide both sides by -2
Final Answer: t< -6</span>