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Luba_88 [7]
3 years ago
15

Hayley has 272 beads.she buys 38 more beads. She will use 89 beads to make bracelets and the rest to make necklaces. She will us

e 9 beads for each necklace. What is the greatest number of necklaces Hayley can make? Show all of your work and write your number in sentence form.
Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0
First, do 272 + 38 = 310
Secondly, do 310 - 89 = 231
Third, do 231 ÷ 9 = 25

The most number of beeds she can have is 25
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QUESTION 3

The sum of the interior angles of a kite is 360\degree.

\Rightarrow 36\degree +70\degree+m.

\Rightarrow 106\degree+m.

\Rightarrow m.

\Rightarrow m.

But the two remaining opposite angles of the kite are congruent.

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\Rightarrow 2m.

\Rightarrow m.

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QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

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|RH|^2=544

|RH|=\sqrt{544}

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QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore m

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

m

\Rightarrow m

\Rightarrow m

QUESTION 7

The sum of the interior angles of a kite is 360\degree.

\Rightarrow 48\degree +110\degree+m.

\Rightarrow 158\degree+m.

\Rightarrow m.

\Rightarrow m.

But the two remaining opposite angles are congruent.

\Rightarrow m

\Rightarrow m.

\Rightarrow 2m.

\Rightarrow m.

\Rightarrow m.

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

|BC|^2=4^2+7^2

\Rightarrow |BC|^2=16+49

\Rightarrow |BC|^2=65

\Rightarrow |BC|=\sqrt{65}

QUESTION 9.

The sum of the interior angles of a trapezium is 360\degree.

\Rightarrow m.

\Rightarrow m.

But the measure of angle M and K are congruent.

\Rightarrow m.

\Rightarrow m.

\Rightarrow m.

\Rightarrow m.

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