Answer:
see below
Step-by-step explanation:
(ab)^n=a^n * b^n
We need to show that it is true for n=1
assuming that it is true for n = k;
(ab)^n=a^n * b^n
( ab) ^1 = a^1 * b^1
ab = a * b
ab = ab
Then we need to show that it is true for n = ( k+1)
or (ab)^(k+1)=a^( k+1) * b^( k+1)
Starting with
(ab)^k=a^k * b^k given
Multiply each side by ab
ab * (ab)^k= ab *a^k * b^k
( ab) ^ ( k+1) = a^ ( k+1) b^ (k+1)
Therefore, the rule is true for every natural number n
Answer:
387, or you can do it another way in the problem if you like/.
Step-by-step explanation:
3x9=27
4x9=36
36+2=38
387
Answer:
the answer for your question would be 1800
Step-by-step explanation:
you multiply 9000 times by .20
Short Answer: 9x + 13
Step by Step:
4x + 5x = 9x
3 + 10 = 13
Hope this helps!
