Using the law of Cosines:
c^2 = 10^2 + 8^2 - 2*10*8*cos(105)
c^2 = 205.41
c = SQRT(205.41)
c = 14.3
The answer is D
Answer:
12 years
Step-by-step explanation:
Given that
P = 5,600 e^0.0591
Reaching amount = 11,200
time period = t
We need to find out the time period i.e. t
So,
11,200 = 5,600 e^0.0591t
2 = e^0.0591t
Now take the log on both the sides
ln2 = 0.0591t ln
t = ln2 ÷ 0.059
= 0.693147÷ 0.059
= 11.748
= 12 years
Answer:
Approximately (2, 1)
See image
Step-by-step explanation:
Rearrange each equation so it is ready to be graphed on an x-y-axis (see image) look for the point where the two lines cross. This is the solution for the system of equations.
Answer:
3
Step-by-step explanation:
(5-4i)-(2-4i)
= 5 - 4i - 2 + 4i
= 5 - 2 - 4i + 4i
= 3
