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jeyben [28]
3 years ago
10

How many different areangements can be made with the word space

Mathematics
1 answer:
kifflom [539]3 years ago
3 0
There are 120 possibilities with 5 letters.
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What is 46,000,000 out of 330,000,000?
wariber [46]
.139


46/300

This would be roughly 14% of 330 million. 

8 0
3 years ago
A cylindrical rod of steel (E = 207 GPa, 30 * 106 psi) having a yield strength of 310 MPa (45,000 psi) is to be subjected to a l
sineoko [7]

Answer:9.477 mm

Step-by-step explanation:

Given

E=207 GPa

Yield Strength(s_{yt}) 310 MPa

load (P)=11,100 N

length of rod(L)=500 mm

\Delta L=0.38 mm

we know \Delta L is given by

\Delta =\frac{PL}{AE}

where A= cross-section

A=\frac{11100\times 500}{0.38\times 207\times 10^9}

A=70.556\times 10^{-6} m^2

A=\frac{\pi d^2}{2}=70.556\times 10^{-6} m^2

d=9.477\times 10^{-3} m

d=9.477 mm

4 0
4 years ago
I REALLY NEED HELP FOR THIS ONE
Natasha2012 [34]

Answer:

<h2>            A = 27(2√3-π) cm² ≈ 8.71 cm²</h2>

Step-by-step explanation:

Area of shaded region it is area of hexagon minus area of circle.

A regular hexagon is comprised of six equilateral triangles (of the same sides).

So its area:  A_1=6\cdot\dfrac{S^2\sqrt3}{4}=\dfrac{3S^2\sqrt3}2     {S = side of the triangle}

Height (H) of such a triangle is equal to radius (R) of a circle inscribed in the hexagon:

R = H = \dfrac{S\sqrt3}{2}

Area of shaded region:

A=A_1-A_\circ=\dfrac{3S^2\sqrt3}2-\pi R^2=\dfrac{6S^2\sqrt3}4-\pi\left(\dfrac{S\sqrt3}2\right)^2=\dfrac{S^2(6\sqrt3-3\pi)}4

S = 6 cm

so:

A=\dfrac{6^2(6\sqrt3-3\pi)}4=\dfrac{36(6\sqrt3-3\pi)}4=9(6\sqrt3-3\pi)=27(2\sqrt3-\pi)\ cm^2\\\\A=27(2\sqrt3-\pi)\ cm^2\approx8.71\ cm^2

3 0
3 years ago
In the figure above, RT = TU. What is<br> the value of x ?<br> A) 72<br> B) 66<br> C) 64<br> D) 58
xz_007 [3.2K]

Answer:

C. 64

Hope that helps you

3 0
3 years ago
While in flight, some hummingbirds can flap their wings about 500 times in 10 seconds
Nookie1986 [14]

Is this a true or false?

3 0
3 years ago
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