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dalvyx [7]
3 years ago
11

What is the value of k?

Mathematics
1 answer:
makkiz [27]3 years ago
7 0

For f(x), when x=1, y=1, and when x=2, y=4. Since the graphs are both quadratic, you can assume f(x)=x².

For g(x), when x=2, y=1, and when x=4, y=4. So g(x)=(x²)÷4.

Now it's a given that g(x) is equivalent to f(k*x), so we can say

(x²)/4=(kx)²

4kx²=x²

k=1/4

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(7t-2)-(-3+1)=-3(1-3t) how do you do this?
Sergeu [11.5K]
<h2>Greetings!</h2>

Answer:

t = \frac{3}{2}

Step-by-step explanation:

First, you need to complete the -3 + 1 and then expand the brackets

-3 + 1 = -2

7t -2 - (-2) = -3(1 - 3t)

Now expant the -3(1 - 3t) bracket

-3 * 1 = -3

-3 * -3t = 9t

7t - 2 - -2 = 9t - 3

The two negatives turn positive:

7t - 2 + 2 = 9t - 3

7t = 9t - 3

Move the -3 over to the oposite side, and also move the +7t over to the +9t, making it a negative:

3 = 9t - 7t

3 = 2t

Divide both sides by 2:

t = \frac{3}{2}

So the value of t is \frac{3}{2}


<h2>Hope this helps!</h2>
6 0
4 years ago
What is another way to write 9 times 200
Whitepunk [10]

200 + 200 + 200 + 200 + 200 + 200 + 200 + 200 + 200 = 1,800

8 0
4 years ago
Z^m-n (z^m+ z^m+n + z^n)
rusak2 [61]

Answer:Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:

(−1)(−1)mn=(−1)n.

It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:

(−1)(−1)mn=(−1)−n=1(−1)n

Multiplying both sides by (−1)n then yields:

1=(−1)2n=[(−1)n]2 which is always true, no matter what n is

8 0
3 years ago
Plzz help <br><br>find value of following : 2sin75°.cos15°​
polet [3.4K]

Answer:

\frac{2+\sqrt{3} }{2}

Step-by-step explanation:

Using the product to sum formula

sinxcosy = \frac{1}{2} [ sin(x + y) + sin(x - y) ] , then

2sinxcosy = sin(x + y) + sin(x - y)

Given

2sin75°cos15° ← with x = 75 and y = 15 , then

= sin(75 + 15) + sin(75 - 15)

= sin90° + sin60°

= 1 + \frac{\sqrt{3} }{2}

= \frac{2+\sqrt{3} }{2}

6 0
3 years ago
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Sati [7]

Answer:

it’s going up by 3 boys per girl!

Step-by-step explanation:

Correct me if I’m wrong by commenting down below.

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