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Anestetic [448]
3 years ago
6

Given the function, g(x)=5x^5/x^3-2x+1, choose the correct horizontal asymptote. none y = 0 y = 1 y = 3

Mathematics
1 answer:
viktelen [127]3 years ago
8 0

Answer:  NONE

<u>Step-by-step explanation:</u>

Consider that m is the degree of the numerator and n is the degree of the denominator.

The rules for horizontal asymptote (H.A.) are as follows:

If m > n   then no H.A. (use long division to find the slant asymptote)

If m = n   then H.A. is y = leading coefficient of numerator/leading coefficient of denominator

If m < n   then H.A. is y = 0

Given: g(x) = 5x⁵/(x³ - 2x + 1)

--> m = 5, n = 3

Since m > n then there is no H.A.

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