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3 years ago

Solve the absolute value inequality: [X + 12[ +5 <27

Mathematics

1 answer:

Westkost [7]3 years ago

5 0

Answer:

Option C.

Step-by-step explanation:

The given absolute value inequality is

$|x+12|+5$

Isolate the absolute value by subtracting 5 from both sides.

$|x+12|+5-5$

$|x+12|+0$

$|x+12|$

Therefore, the correct option is C.

We can further solve this, to find the solution of the given inequality.

$-22$

Subtract 12 from each sides.

$-22-12$

$-34$

The solution of given inequality is $-34$ .

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In ΔKLM, the measure of ∠M=90°, LK = 97, ML = 65, and KM = 72. What is the value of the sine of ∠L to the nearest hundredth?

Sphinxa [80]

Answer:

0.74

Step-by-step explanation:

72/97 is 0.74 rounded to the nearest hundredths.

6 0

3 years ago

What is the inverse of the function f(x) = 2x + 1?

BaLLatris [955]

Answer:

$f^{-1} = \frac{x-1}{2}$

Step-by-step explanation:

$f(x) = 2x+1$

Replace it with y

$y = 2x+1$

Exchange the values of x and y

$x = 2y+1$

Solve for y

$x = 2y+1$

Subtracting 1 from both sides

$2y = x-1$

Dividing both sides by 2

$y = \frac{x-1}{2}$

Replace it by $f^{-1}$

So,

$f^{-1} = \frac{x-1}{2}$

3 0

4 years ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

4 years ago

Wrote a problem for the equation 0.5n= 12.5.

statuscvo [17]

Emma wanted to buy some apples from the store. They each cost $0.5. If Emma paid $12.5 in total, how many apples did Emma buy?

6 0

3 years ago

No fakes please! Ill give brainliest!!!

Andreas93 [3]

Step-by-step explanation:

1. 5/8 = 62.5%

2. 1/5 = 20%

3. 4 2/3 = 4.66%

8 0

3 years ago