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Wewaii [24]
3 years ago
11

Solve the absolute value inequality: [X + 12[ +5 <27

Mathematics
1 answer:
Westkost [7]3 years ago
5 0

Answer:

Option C.

Step-by-step explanation:

The given absolute value inequality is

|x+12|+5

Isolate the absolute value by subtracting 5 from both sides.

|x+12|+5-5

|x+12|+0

|x+12|

Therefore, the correct option is C.

We can further solve this, to find the solution of the given inequality.

-22

Subtract 12 from each sides.

-22-12

-34

The solution of given inequality is -34.

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In ΔKLM, the measure of ∠M=90°, LK = 97, ML = 65, and KM = 72. What is the value of the sine of ∠L to the nearest hundredth?
Sphinxa [80]

Answer:

0.74

Step-by-step explanation:

72/97 is 0.74 rounded to the nearest hundredths.

6 0
3 years ago
What is the inverse of the function f(x) = 2x + 1?
BaLLatris [955]

Answer:

f^{-1} = \frac{x-1}{2}

Step-by-step explanation:

f(x) = 2x+1

<em>Replace it with y</em>

y = 2x+1

<em>Exchange the values of  x and y</em>

x = 2y+1

<em>Solve for y</em>

x = 2y+1

<em>Subtracting 1 from both sides</em>

2y = x-1

<em>Dividing both sides by 2</em>

y = \frac{x-1}{2}

<em>Replace it by </em>f^{-1}

So,

f^{-1} = \frac{x-1}{2}

3 0
4 years ago
Read 2 more answers
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
4 years ago
Wrote a problem for the equation 0.5n= 12.5.
statuscvo [17]
Emma wanted to buy some apples from the store. They each cost $0.5. If Emma paid $12.5 in total, how many apples did Emma buy?
6 0
3 years ago
No fakes please!<br> Ill give brainliest!!!
Andreas93 [3]

Step-by-step explanation:

1. 5/8 = 62.5%

2. 1/5 = 20%

3. 4 2/3 = 4.66%

8 0
3 years ago
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