1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mixas84 [53]
3 years ago
7

Can someone help me with this one?​

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

7 and 3/10

Step-by-step explanation:

You might be interested in
The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont
anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

<u>a)</u><u> The preset value equation is given by this formula:</u>

P=\int^{T}_{0}f(t)e^{-rt}dt

where:

  • T is the period in years (T = 10 years)
  • r is the annual interest rate (r=0.08)

So we have:

P=\int^{T}_{0}(0.01t+100)e^{-rt}dt

Now we just need to solve this integral.

P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt

P=e^{-0.08t}(-1.56-0.13t)|^{10}_{0}+1250e^{-0.08t}|^{10}_{0}

P=0.30+688.34=688.64 $

The present value is 688.64 $

<u>b)</u><u> The accumulated amount of money flow formula is:</u>

A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P

A=e^{0.08\cdot 10}688.64=1532.60 $

The accumulated amount is 1532.60 $

Have a nice day!

6 0
3 years ago
The acceleration (m/sec2) of an object along a straight une is given in the following graph:
kirill [66]
I not sure of the answer
6 0
3 years ago
Problem #1 HELP SHOW WORK PLS
OLEGan [10]

Answer: 30 degrees

Step-by-step explanation:

Corresponding angles of similar triangles are congruent.

5 0
1 year ago
Please help ASAP
salantis [7]

Answer:

0.5 m/s

Falling at 32 feet/s

Step-by-step explanation:

For the first question, since it only asks for the average time between 2 and 8 seconds, those are the only two important values. When taking the inputs and outputs for 2 and 8 seconds after the throw ((2,3) and (8,6) respectively), we can take the average change by finding the change in y/change in x, so we have (6-3)/(8-2)=0.5 meters/second.

For the second question, we can similarly just take the values from the initial drop (144) and after two seconds (80) to get that the rate of change is (144-80)/(-2)=-32, so it's falling at 32 feet/second.

Let me know if you have any questions!

8 0
3 years ago
Read 2 more answers
How do you interpret the value of the mean or the median in a situation
natka813 [3]

Answer:

Adding all the numbers together and dividing by the number of numbers

Example:

1, 3, 5, 6, 6, 6, 8, 8, 35, 46

Adding them together results in 124

124 divded by the number of numbers is 124 / 10 = 12.4

So the mean / median in this example is 12.4

(I think, hopefully this helps and I hope you have a nice day!)

3 0
3 years ago
Other questions:
  • alaina owes her mom $15 and her friend $27. then she babysat and earned $35. how much more money does alaina need to earn in ord
    13·1 answer
  • The volume of this triangular prism is 64 cubic inches. what is the value of G?
    13·1 answer
  • Javier earned $820 dollars this week .he net income was $683.20.he paid $95.60 in federal income tax. How much did Javier pay in
    9·2 answers
  • Quiz
    10·1 answer
  • Please i really need help on this.
    10·1 answer
  • Given the regular nonagon, solve for x and y.
    10·1 answer
  • The area covered by a topic lie plant triples every year. By what factors does the are covered by the plant increase every month
    9·1 answer
  • A 2-cup bottle of shampoo costs $11.20. What is the price per fluid ounce?
    15·2 answers
  • Determined to find the slope<br>(1,7K) and (-3,5k)​
    9·1 answer
  • A golf player is trying to make a hole-in-one on the miniature golf green shown.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!