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pychu [463]
3 years ago
6

2x-4=-3x+6 what is the answer

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

x=2

Step-by-step explanation:

Put all like terms on one side:

2x+3x=6+4

Simplify:

5x=10

x=2

<em>~Stay golden~ :)</em>

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Which has least value when x=100?
Julli [10]

                - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

          Which expression has least value when x=100?

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond

Substitute 100 for x and solve:-

\bold{\dfrac{1}{100}}

\bold{\dfrac{10}{100}}

\bold{1-100=-99}

\bold{10-100=-90}

Since -99 is the smallest number here, the expression with the least value when x=100 is Option C - \checkmark\dashrightarrow\boxed{\boxed{1-x}}}\dashleftarrow\checkmark

<h3>Good luck.</h3>

          - - -- - - - - - - - - - - - - - - - - - - -- - - - -

7 0
2 years ago
What is the reciproncal of fraction 2 5th
ELEN [110]
The reciprocal of the fraction 2/5 is 5/2. Remember a reciprocal is the reverse of a fraction.
7 0
4 years ago
Read 2 more answers
Did more than five times a number (x) is at least twenty one
yanalaym [24]
5(x)=21

five times a number is a least 21

8 0
3 years ago
State the number of possible triangles that can be formed using the given measurements.
romanna [79]

Answer:  39) 1              40) 2

                41) 1              42) 0

<u>Step-by-step explanation:</u>

39)     ∠A = ?        ∠B = ?       ∠C = 129°

            a = ?          b = 15         c = 45

Use Law of Sines to find ∠B:

\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36°        ∠B = 15°       ∠C = 129°       is the only valid solution.

40)      ∠A = 16°        ∠B = ?       ∠C = ?

             a = 15           b = ?         c = 19

Use Law of Sines to find ∠C:

\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1:  ∠A = 16°        ∠B = 144°       ∠C = 20°    

Solution 2:  ∠A = 16°        ∠B = 4°       ∠C = 160°    

41)       ∠A = ?        ∠B = 75°       ∠C = ?

             a = 7           b = 30         c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13°        ∠B = 75°       ∠C = 92°       is the only valid solution.

42)      ∠A = ?         ∠B = 119°       ∠C = ?

             a = 34         b = 34           c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

6 0
3 years ago
Evaluate the algebraic expression 18 + (- 31) =
frosja888 [35]

Answer:

-13

Step-by-step explanation:

8 0
3 years ago
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