Think of the SS numbers as being a collection of digits. If any of the digits (say the first one for example) are 8 then all the remaining digits can be anything but 8, meaning there are 9 choices for each remaining digit. This effectively becomes an 8 digit number with the constraint that there can only be 9 choices for a digit. This means for the first digit being 8 we have 9⁸ remaining possible numbers. Since we will do this for each of the remaining digits (they each get to be 8 then we count their 9⁸ configurations) we end up with 9(9⁸) or 9⁹≈3.8742E8
Answer:
300%
Step-by-step explanation:
3 difference increase
Any number raised to the power of 0 is 1.
(z^3)^4(q^3)^0 = (z^3)^4 = z^(3 x 4) = z^12
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