Answer:segment YZ ≈ 19.4 inangle X ≈ 85.3°angle Z ≈ 26.7°Explanation:1) Given two side lenghts and one angle you can use sine law:

2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:

From which you can clear sinZ and get:
sinZ = 43 × sin(68) / 40 = 0.9967
⇒ Z = arcsine(0.9967) ≈ 85.36°
3) The third angle can be determined using 85.36° + 68° + X = 180°
⇒ X = 180° - 85.36° - 68° = 26.64°.
4) Finally, you can apply the law of sine to obtain the last missing length:

From which: x = 40 × sin(26.64°) / sin(68°) = 19.34 in
The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
Answer:
Lies in the shaded regions of both the top and bottom inequalities.
Step-by-step explanation:
The point of solution for BOTH systems of inequalities must work for both equations. Therefore, the point has to lie in both top and bottom shaded regions or it won't work for both, but just one.
M + R + G = 119
G = 3M
M = R + 6 —> R = M - 6
1st equation: M + (M-6) + (3M) = 119
5M -6 = 119
5M = 125
M = 25
G = 3(25) = 75
R = (25) -6 = 19