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olga2289 [7]
3 years ago
13

Pls help find the area of the smaller sector.

Mathematics
1 answer:
Lunna [17]3 years ago
7 0

I'm good at math but Idk this sorry

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Need help please show how to complete
Mice21 [21]
Answer: 4). A = (b1 + b2)h/2
5).
A = (b x h)/2
6). A = b x h
7). A = b x h = 65 x 50 = 3250 ft^2
8). A = (b x h)/2 = (12 x 18)/2 = 108 inches^2
9). A = (b1 + b2)h/2 = (15 + 7)4/2 = 44m^2
8 0
3 years ago
Read 2 more answers
Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x .
harina [27]
  3              1                   10
------ + --------------- =  ----------
 3x          x +4                 7x

      1            1                 10
    ------ + ------------ =  ----------
      x          x +4               7x


       x + 4 + x           10               
   ------------------ =  ----------
       x(x +4)             7x

       2x + 4                10               
 ------------------ =  ----------
       x(x +4)                7x

    7x(2x + 4) = 10x(x+4)
  
  14x^2 + 28x = 10x^2 + 40x

  4x^2  - 12x = 0
  4x(x - 3) = 0
  4x = 0
    x = 0
 x - 3 = 0
      x = 3

answer x = 0 and x = 3




8 0
3 years ago
Read 2 more answers
Write as a polynomial: <br><br> 2a^2(a-1)(3-a)
seropon [69]

Answer:

-2a^4+8a^3-6a^2

Step-by-step explanation:

2a^2(a-1)(3-a)

2a^2(-a^2 +3a-3+a)

2a^2(-a^2+4a-3)

-2a^4+8a^3-6a^2

6 0
2 years ago
Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
Over the last three evenings, Debra received a total of 110 phone calls at the call center. The second evening, she received 4 t
Elza [17]

Answer:

See below.

Step-by-step explanation:

Total = 110

Let calls on third evening = x

second evening = 4x

first evening = x + 8

=> x + 4x + x + 8 = 110

=> 6x = 102

=> x = 17

First evening = x = 17 calls

Second evening = 4x = 68 calls

Third evening = x + 8 = 25 calls

4 0
1 year ago
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