Slope-intercept form is y = mx + b
So we can manage to do this:
(y - yo) = m.(x - xo)
Where (x, y) and (xo, yo) are points of this line, this way we can discover the slope.
(7 - 2) = m.(1 - 0)
5 = m
m = 5
So,
y = 5x + b
Now we still have to use (y - yo) = m.(x - xo), but this time we will put only 1 point and the slope.
(y - yo) = m.(x - xo)
(y - 2) = 5.(x - 0)
y - 2 = 5x
y = 5x + 2
So, this is the line in slope-intercept form.
Answer:

Step-by-step explanation:
From the given information:
The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.
Now, let V(x) be the time needed for the runner to reach the buoy;
∴ We can say that,

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.
i.e
The differential of V(x) = V'(x) =0
=





squaring both sides; we get


By cross multiplying; we get










Answer: I believe the answer would be about 1
hope this helps