Answer:
Please check the explanation.
Step-by-step explanation:
Let the coordinates of the point F be (x, y).
When a point F(x, y) is reflected over the x-axis, the x-coordinate of the point F remains the same, and the y-coordinate of the point reverses the sign.
Thus, the rule of reflection over the x-axis:
F(x, y) → F'(x, -y)
Here,
F'(x, -y) would be coordinates of point F after the reflection over the x-axis.
Let say, the point F(1, 2).
The coordinate of the point F after the reflection over the x-axis would be:
F(1, 2) → F'(1, -2)
Thus, F'(1, -2) would be the coordinates of point F after the reflection over the x-axis.
1)inside the triangule is 180º .There are 3 angules, one with 120º, theta and
angle ACB, lets call it x.
x + theta + 120 = 180
x + theta= 180-120
x + theta= 60
x= 60- theta
angle ACB= 60- theta
Point-slope form: y-y1 = m(x-x1)
Standard form: ax + by = c
Slope-intercept form: y = mx+b
Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.
To create point-slope form, we need to get one point from the graph. Let's use (3,0).
To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.
To get standard form, solve the equation in terms of C.
Point-slope form: y = -4/3(x-3)
Slope-intercept form: y = -4/3x + 4
Standard form: 4/3x + y = 4
Answer:
The equation of the Parallel line to the given line is 5x+y-7=0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the line y = - 5x+4 and point (1,2)
The equation of the Parallel line to the given line is ax+by+k=0
Given straight line 5x + y -4 =0
The equation of the Parallel line to the given line is 5x+y+k=0
This line passes through the point (1,2)
5x+y+k=0
5(1)+2+k=0
⇒ 7+k=0
k =-7
<u>Final answer:-</u>
The equation of the Parallel line to the given line is 5x+y-7=0
