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natta225 [31]
3 years ago
15

A bottle of ketchup holds .946 letters. how many milliliters will the ketchup bottle hold

Mathematics
1 answer:
adoni [48]3 years ago
4 0
The bottle will hold 946 milliliters if it holds .946 liters 
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The graph of f(x) = (0.5) is replaced by the graph of g(x) = (0.5)* - k. If g(x) is obtained by shifting f(x) down by 3 units, t
Ghella [55]

Answer:

k = 3

Step-by-step explanation:

Given

f(x) = 0.5x

g(x) = 0.5x - k

Required

Find\ k

Initial expression of f(x) is f(x) = 0.5x

From the question; we understand that f(x) was shifted down by 3 units;

This implies that

New\ f(x) = 0.5x - 3

Also from the question; we understand that this new f(x) is equivalent to g(x);

In other words;

New\ f(x) = g(x)

SubstituteNew\ f(x) = 0.5x - 3 and g(x) = 0.5x - k

This gives

0.5x - 3 = 0.5x - k

<em />

Subtract 0.5x to both sides

0.5x - 3 - 0.5x = 0.5x - k - 0.5x

Rearrange

0.5x - 0.5x - 3 = 0.5x  - 0.5x- k

-3 = -k

Multiply both sides by -1

-3 * -1 = -k *-1

3 = k

k = 3

5 0
2 years ago
Tiger cubs are around 2 years old when they leave their mothers. In the wild, tigers live about 11 years. About what percent of
pogonyaev

Answer:

18.18%

Step-by-step explanation:

Cross-multiply

11 years ------------ 100% of life

2 years ------------- x% of life

11/2 = 100/x ===> 11x = 2*100 ===> 11x = 200 ===> x = 200/11 ===> x = 18.18%

5 0
2 years ago
At the local sandwich shop, employees earn double time for any hours worked in addition to their regular 40-hour week. Last week
Monica [59]
40×8.50=340 17×9=153 153+340=493 regular time/Double time add together
7 0
3 years ago
Read 2 more answers
Ax + z = aw - y<br> Solve for a
olga2289 [7]
Ax=aw-z-y
divide by x
a=awx-z-y
a=awx-zy
8 0
2 years ago
 A country has a total biocapacity of 6.21 ha/person, a biocapacity of grazing land of 0.85 ha/person, and a biocapacity of for
yanalaym [24]

Answer:

3.38/6.21=54.428% (0.54428)

Step-by-step explanation:

biocapacity of grazing land of 0.85 ha/person+biocapacity of forest land of 2.53 ha/person

2.53+0.85=3.38

the percentage of biocapacity from grazing and forest land

3.38/6.21=54.428% (0.54428)

3 0
3 years ago
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