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solniwko [45]
4 years ago
10

Is it virtually impossible to completely avoid criticism

Mathematics
1 answer:
grin007 [14]4 years ago
6 0

Well yes but this doesn't belong in math by the way.

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SOME ONE PLEASE HELP Determine the sum: (8x3y2 + 4xy2) + (2xy2 + 9x3). 23x8y6
Nostrana [21]
The answer is this:

<span><span><span>8<span>x^3</span></span><span>y^2</span></span>+<span>9<span>x^3</span></span></span>+<span><span>6x</span><span>y^<span>2</span></span></span>
8 0
4 years ago
93 x 18=<br> Multiply and show work
pantera1 [17]

Answer:

Step-by-step explanation:93x18= 1674

3 0
3 years ago
The length of a rectangle is twice its width. if the perimeter of the rectangle is 54 ft , find its length and width.
polet [3.4K]
Let w be the width.

2(2w) + 2w = 54.

4w+2w = 54
6w=54.
w=9
So length equals twice that...I think you can solve that on your own. xD
7 0
4 years ago
NEED HELP ASAP, WILL GIVE BRAINLIEST
Stella [2.4K]

Given:

The equation of circle is

(x+3)^2+y^2=9

To find:

The polar form of given circle.

Solution:

We have,

(x+3)^2+y^2=9

x^2+2(x)(3)+(3)^2+y^2=9        [\because (a+b)^2=a^2+2ab+b^2]

(x^2+y^2)+6x+9=9

Subtracting 9 from both sides, we get

(x^2+y^2)+6x=0

We know that, x^2+y^2=r^2 and x=r\cos \theta.

r^2+6(r\cos \theta)=0

r(r+6\cos \theta)=0

r=0 and r+6\cos \theta=0

We know that, r is radius it cannot be 0. So,

r+6\cos \theta=0

r=-6\cos \theta

Therefore, the correct option is A.

4 0
3 years ago
Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu
SOVA2 [1]
Eloise made these steps well:
 Square root of negative 2x plus 1 - 3 = x
 Square root of negative 2x plus 1 - 3 + 3 = x + 3
 The error comes in the next step:
 Square root of negative 2x plus 1 = x + 3
 Square root of negative 2x plus 1 -1 = x + 3 - 1
 Square root of negative 2x  = x + 2
 the number one is inside the root, therefore they can not be subtracted.
 answer
 error in the step:
  Square root of negative 2x  = x + 2

5 0
3 years ago
Read 2 more answers
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