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2 years ago

Please help!!! Math is not my thing

Mathematics

2 answers:

blsea [12.9K]2 years ago

5 0

C. 7/8 is larger than 1/5

nikitadnepr [17]2 years ago

3 0

C Is the answer
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At the bulk food store, Stacy bought 7 lbs of nuts. She used 8 ounces of nuts in a recipe and then put the rest of the nuts into

chubhunter [2.5K]

Answer:

A. 26

Step-by-step explanation: there is 16oz in every lb. so 16 X’s 7=112 now minus the 8ozs used. 112-8=104 oz’s left. The snack bags are 4 ozs so you Divide 4/104=26

3 0

3 years ago

Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula? Qu

Likurg_2 [28]

Answer:

a = 1

b = -1

c = -2

Step-by-step explanation:

We reorder the equation in such way that let us see the usual

ax² + bx + c = 0

Then the original quation is:

-2 = - x + x² - 4 ⇒ 0 = 2 - x + x² - 4 ⇒ x² - x - 2 = 0

Now we are able by simply inspection to identify a, b . c comparing our equation with the general equation so :

a = 1

b = -1

c = -2

5 0

3 years ago

Read 2 more answers

Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

5 0

3 years ago

Can y’all help me and tell me what the answer is please I’m a bit stuck

12345 [234]

Answer:

The correct choice is:

-2 to the 4th power is positive 16.

Option C is correct.

Step-by-step explanation:

We need to find mistake make in work below:

$(-2x^4)^4=-16x^{16}$

The mistake here is when we have even power, the negative sign gets positive i.e $(-a)^m=a^m$ if m is even

so, in our case it would be:

$(-2x^4)^4=16x^{16}$

The correct choice is:

-2 to the 4th power is positive 16.

Option C is correct.

5 0

2 years ago

PLEASE HELP ASAP 25 POINTS

dimaraw [331]

Answer:

the answer is d

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers