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2 years ago

Use the table to work out the values of a, b, c, and d.

Mathematics

2 answers:

ch4aika [34]2 years ago

8 0

Answer:

First one is -3 2nd is 0 the 3rd one is 6 and the last one is 9

Step-by-step explanation:

kvasek [131]2 years ago

4 0

Answer:

a=-3, b=0, c=6, d= 9

Step-by-step explanation:

simply subsitute the corresponding x in the equation y=3x+3 for each letter.

for a, do y=3(-2)+3➡ y=-6+3➡y=-3

for b, do y=3(-1)+3➡y=-3+3➡y=0

for c, do y=3(1)+3➡y=3+3➡y=6

for d do, y=3(2)+3➡y=6+3➡y=9

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Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

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$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

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3 years ago

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Use the table to work out the values of a, b, c, and d.​

Use the table to work out the values of a, b, c, and d.