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strojnjashka [21]
3 years ago
13

Jenna found three solution to a linear equation she graphed them, but they don't lie in a straight line. What errors could jenna

have made? Explain.
Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.

A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.

There are many different methods in arriving to the final answer. However, errors cannot be perfectly avoided. One of these errors to mistakenly identify equations as linear. It is important that we know that the equations we are dealing with are of exact or correct  characteristics.

Also, if she had used substitution method, she might have mistakenly taken the value of one variable for the other.

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Janet is designing a frame for a client. She wants to prove to her client that m∠AGE ≅ m∠CHE in her sketch. What is the missing
Amiraneli [1.4K]

Answer:

I believe the answer is transative property. I'm currently taking the test so I'm not 100% sure if I'm right yet.

Step-by-step explanation:

In step one, AGE and HGB are verticle angles since they are opposite of each other. then step two is alternate interior angles because they are interior angles opposite of each other, self-explanatory. the reason I choose the transitive property over the corresponding angles theorem is because the transitive property states: among A B and C, if A=B and B=c then A=C and in this case since AGE=HGB andHGB=CHE then AGE=CHE. I hope this helps and if you know the right answer just put it in the comments, if I'm wrong ofc.  

6 0
3 years ago
A central angle of a circle measures 1.5 radians. If the radius of the circle is 3 cm, what is the area of the related sector?
soldi70 [24.7K]

Answer:

Option B. 6.75\ cm^{2}

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^{2}

we have

r=3\ cm

substitute

A=\pi (3^{2})=9 \pi\ cm^{2}

Remember that

2\pi radians subtends the complete circle of area 9 \pi\ cm^{2}

so

by proportion

Find the area of the related sector for a central angle of 1.5 radians

Let

x------> the area of the related sector

\frac{9 \pi}{2\pi}\frac{cm^{2}}{radians} =\frac{x}{1.5}\frac{cm^{2}}{radians}\\ \\x=9*1.5/2\\ \\x= 6.75\ cm^{2}

7 0
3 years ago
Help me plz this is due rn
Sedaia [141]

Answer:

1/3

Step-by-step explanation:

7 0
3 years ago
Helppp!!!<br> Simplify this. Please explain it too.<br><br> 18x^4 – 3x^3 – 2x^3 + x^2 – 10 + 6
strojnjashka [21]

Answer: 18x^4 - 5x^3 + x^2 - 4

Step-by-step explanation:

We need to add like terms.

-10 and 6 are like terms

-10 + 6 = - 4

-3x^3 and -2^3 are like terms

-3x^3 + -2^3 = -5x^3

There are no other like terms.

18x^4 - 5x^3 + x^2 - 4

5 0
3 years ago
Given f(x) = 5x + 3, find f(5)
Neko [114]

Answer:

Hey there!

f(x)=5x+3

f(5)=5(5)+3

f(5)=25+3

f(5)=28

Let me know if this helps :)

5 0
3 years ago
Read 2 more answers
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