Choice given:
<span>33.6°
39.8°
50.2°
56.4°
I drew the figure.
I got 12 ft as the hypotenuse, 10 ft as the opposite.
Sin</span>Θ = opposite / hypotenuse
SinΘ = 10/12
SinΘ = 0.83
I used the calculator to get the value of each angle using the sine function
sin(33.6°) = 0.55
sin(39.8°) = 0.64
sin(50.2°) = 0.77
sin(56.4°) = 0.83
The angle where the wire meets the ground is approximately 56.4°
Answer:
36.56 in
Step-by-step explanation:
perimeter is the sum of all sides
u add all the sides of the square by 6
6+ 6 + 6 + 6 = 24
circumference is the line around the circle
circumference = 3.14 x diameter
c = 3.14 x 4
c = 12.56
24 + 12.56 = 36.56
to the NEAREST HUNDREDTH????? ok welll thats alr
remember
5 or more, raise the score
4 or less, let it rest
this should be fine since the last 6 is alr in the hundredth place :)
like this up !!
Answer:
24
Step-by-step explanation:
4xy
4(2)(3)
24
We have to prove that rectangles are parallelograms with congruent Diagonals.
Solution:
1. ∠R=∠E=∠C=∠T=90°
2. ER= CT, EC ║RT
3. Diagonals E T and C R are drawn.
4. Shows Quadrilateral R E CT is a Rectangle.→→[Because if in a Quadrilateral One pair of Opposite sides are equal and parallel and each of the interior angle is right angle than it is a Rectangle.]
5. Quadrilateral RECT is a Parallelogram.→→[If in a Quadrilateral one pair of opposite sides are equal and parallel then it is a Parallelogram]
6. In Δ ERT and Δ CTR
(a) ER= CT→→[Opposite sides of parallelogram]
(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]
(c) Side TR is Common.
So, Δ ERT ≅ Δ CTR→→[SAS]
Diagonal ET= Diagonal CR →→→[CPCTC]
In step 6, while proving Δ E RT ≅ Δ CTR, we have used
(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]
Here we have used ,Option (D) : Same-Side Interior Angles Theorem, which states that Sum of interior angles on same side of Transversal is supplementary.