So 15 gallons of gas brought it from 1/8 full to 3/4 full.
Let's change 3/4 to the equivalent fraction 6/8 so that the denominators are the same. (3/4 = 6/8)
So 15 gallons of gas brought it from 1/8 to 6/8 Those 15 gallons must be 5/8 of the tank's capacity 6/8 - 1/8 = 5/8
So 15 is 5/8 of what number? (This will tell us the capacity of the whole tank)
15 = 5/8n
Divide both sides by 5/8 (remembering to multiply by the reciprocal 8/5)
15 ÷ 5/8 = 15 x 8/5 = 18
So the tank holds 24 gallons and (since it is 3/4 full or has 18 gallons) it needs 6 gallons to fill the tank.
Check - at first 1/8 full (1/8 of 24 = 3) So we started with 3 gallons. 15 gallons added to the 3 gallons is 18 gallons. Now the tank is 6/8 (3/4 full). The remaining 1/4 (2/8) of a tank is the difference between 18 and it's capacity (24 gallons) so it will need 6 gallons to fill it up..
The distance between -4/12 and 9 is
-369/2
Step 1 :
41
Simplify ——
2
Equation at the end of step 1 :
41
((((0 - ——) • a) • n) • d) • 9
2
Step 2 :
Final result :
-369and
———————
2
10x10x10x10x10
These Extra letters mean nothing difufnfhvhfjfjdjfjggybjfjffjfj
Answer:42.98
Step-by-step explanation:
Hf=√(11^2-8^2)
Hf=√(121-64)
Hf=√(57)
Hf=7.5
11/sin90 =7.5/sinG
Sin90=1
11/1=7.5/sinG
Cross multiply
11 x sinG=7.5 x 1
11sinG=7.5
Divide both sides by 11
11sinG/11=7.5/11
sinG=0.6818
G=sin(inverse)(0.6818)
G=42.98
Answer:
The period of Y increases by a factor of 
with respect to the period of X
Step-by-step explanation:
The equation 
shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?
For the planet Y:
For planet X:
To know the factor of aumeto we compared 
with 
We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:
So
Then, the period of Y increases by a factor of with respect to the period of X
