Answer:
In the picture above.
Step-by-step explanation:
First: I solved the right side to get y=93.
Second:calculate the triangle to get z=15.
Third: x=90.
Answer:
The answer is 1 - 16b.
Step-by-step explanation:
You have to collect like-terms :




move the decimal point to the nearest significant number
7.353
you have moved the decimal point 5 places, so what you put is 10^5
7.353 x 10^5 is your answer
hope this helps
The probability of getting 3 or more who were involved in a car accident last year is 0.126.
Given 9% of the drivers were involved in a car accident last year.
We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.
We have to use binomial theorem which is as under:
n
where p is the probability an r is the number of trials.
Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]
=1-{
}
=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}
=1-{0.2670+0.3654+0.2358}
=1-0.8682
=0.1318
Among the options given the nearest is 0.126.
Hence the probability that 3 or more are involved in the accident is 0.126.
Learn more about probability at brainly.com/question/24756209
#SPJ4