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aleksandrvk [35]
3 years ago
9

What is the slope of the line x=4 ?

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0
There’s no slope because it’s a vertical line.
ratelena [41]3 years ago
3 0

Answer:

Step-by-step explanation:

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Write an equation in slope-intercept form for the line.<br><br> slope = 0, y-intercept = 3
Anit [1.1K]

Answer:  y = 0x+3 or y = 3

The slope is 0 and the y intercept is 3. So m = 0 and b = 3.

Plug those into y = mx+b to get y = 0x+3, and that simplifies to y = 3.

This graphs out a horizontal line that passes through the two points (0,3) and (1,3).

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3 years ago
Find all the solutions of the equation in the interval [0,2pi). 4sin^(2)x=5-4cosx
gulaghasi [49]
                       4sin²(x) = 5 - 4cos(x)
        4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
   4{¹/₂[1] - ¹/₂[cos(2x)]} = 5 - 4cos(x)
         4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
     4[¹/₂] - 4[¹/₂cos(2x)] = 5 - 4cos(x)
                2 - 2cos(2x) = 5 - 4cos(x)
              - 2                   - 2
                    -2cos(2x) = 3 - 4cos(x)
            -2[2cos²(x) - 1] = 3 - 4cos(x)
               -4cos²(x) + 2 = 3 - 4cos(x)
                               - 2  - 2
                     -4cos²(x) = 1 - 4cos(x)
-4cos²(x) + 4cos(x) - 1 = 0
 4cos²(x) - 4cos(x) + 1 = 0
               [2cos(x) - 1]² = 0
                  2cos(x) - 1 = 0
                              + 1 + 1
                       2cos(x) = 1
                            2         2
                         cos(x) = ¹/₂
                cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
                                 x = 60, 300
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[0, 2π) = 0 ≤ x < 2π
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Step-by-step explanation:

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