Even integers have the form 2k so three consecutive even integers will be 2k,2(k+1),2(k+2)
so there sum will be
2k+2(k+1)+2(k+2)=24
simplifying
2k+2k+2+2k+4=24
adding like terms
6k+6=24
6k=18
k=3
so the three consecutive even integers are
2(3),2(3+1),2(3+2)
6,8,10
Answer:
P(1, π/4)
P(-1, π/4)
P(4, 5π/6)
P(-4, 5π/6)
Step-by-step explanation:
Knowing the formulas
r = √(x²+y²)
θ = Arctg (y/x)
we have
a) P(1, 1)
i)
r = √(1²+1²) = +1
r = +1
θ = Arctg (1/1) = π/4
P(1, π/4)
ii) r = √(1²+1²) = -1
r = -1
θ = Arctg (1/1) = π/4
P(-1, π/4)
b) P(2√3, -2)
i)
r = √((2√3)²+(-2)²) = +4
r = +4
θ = Arctg (-2/2√3) = 5π/6
P(4, 5π/6)
ii)
r = √((2√3)²+(-2)²) = -4
r = -4
θ = Arctg (-2/2√3) = 5π/6
P(-4, 5π/6)
Answer:
the answer is 40
Step-by-step explanation:
x+60
x=60-20
x=20
Answer:
i thingk u can do it
Step-by-step explanation:
She totally missed seeing the number 30, as 15 x 2 is 30 and 6 x 5 is 30. 30 is her LCM
