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Keith_Richards [23]
3 years ago
10

What is a coefficient?

Mathematics
2 answers:
iogann1982 [59]3 years ago
6 0
Coefficient is the number before your variable. :)
AfilCa [17]3 years ago
4 0

In mathematics, a coefficient is the number in front of your variable. So it's a numerical factor within a term that is multiplied by the variable which is a letter used to represent any number or a symbol used to represent an unknown value.

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F(x)= 9x + 2 over 3X^2+5x-12
Maurinko [17]
Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)

Factor the denominator to find the excluded values of x...

3x^2+5x-12

3x^2+9x-4x-12

3x(x+3)-4(x+3)

(3x-4)(x+3)

So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:

x=(-oo, -3),(-3, 4/3),(4/3, +oo)
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Of the service calls Mike revives, 40% are for air conditioners and 1/5 are for heaters. What percent represents the amount of a
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40% represents the other.

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weeeeeb [17]

Answer:

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Step-by-step explanation:

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3 years ago
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Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.
Blizzard [7]

Answer:

The answer is

y = 3

y =  - 4

Step-by-step explanation:

We must find a solution where

\frac{6}{y + 1}  +  \frac{y}{y - 2}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

\frac{6}{y + 1}  \times  \frac{y - 2}{y - 2}  +  \frac{y}{y - 2}  \times  \frac{y + 1}{y + 1}

Which equals

\frac{6y - 12}{(y -2) (y + 1)}  +  \frac{ {y}^{2} + y }{(y - 2)(y + 1)}

Add the fractions

\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Simplify the right side by multiplying the fraction

\frac{6y}{(y  + 1)(y + 2)}

Set both fractions equal to each other

\frac{6y}{(y + 1)(y - 2)}  =  \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}

Since the denomiator are equal, we must set the numerator equal to each other

6y =  {y}^{2}  + 7y - 12

=  {y}^{2}  + y - 12

(y  + 4)(y - 3)

y =  - 4

y = 3

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Point b is the correct answer love!
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