$s = ut + \frac{1}{2} a {t}^{2} \\ s = 10( \frac{1}{2} ) + \frac{1}{2} ( - 2) {( \frac{1}{2}) }^{2} \\ s = 10( \frac{1}{2} ) + \frac{1}{2} ( - 2)( \frac{1}{4} ) \\ s = 5 + ( - 1)( \frac{1}{4} ) \\ s = 5 + ( - \frac{1}{4} ) \\ s = 5 - \frac{1}{4} \\ s = \frac{20}{4} - \frac{1}{4} \\ s = \frac{19}{4}$

Hope it helps

Please give brainliest

4 0

2 years ago

Read 2 more answers

If AB = 12, AC = 16, and ED = 5, find AE.

AleksAgata [21]

Answer:

AE =15

Step-by-step explanation:

BC=16-12 = 4

AE=x

12/4 = x/5

Cross multiplication

4x=60

x=15

4x3 = 12

5x3 =15

5 0

2 years ago

In which section of the number line is √5?

Ymorist [56]

We know that $\sqrt(4)$ and $\sqrt(9)$ are 2 and 3 respectively. Therefore, $/sqrt(5)$ is between 2 and 3, approximately 2.2.

6 0

3 years ago

A dataset shows that, on average, smokers do not live as long as nonsmokers and heavy smokers do not live as long as light smoke

leva [86]

<span>Given that A dataset shows that, on average, smokers do not live as long as nonsmokers and heavy smokers do not live as long as light smokers.

If you compute the least squares line for y = age at time of death and x = number of packets per day typically smoked, you will notice that as the number of packets per day a person smokes increases, the age at time of death of the person decreases.

Thus, the graph wil have a negative slope.

Therefore, the slope of your regression line will be less than 0.</span>

8 0

3 years ago