The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.

$\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]$

The product will result in the solution for the x- and y-values of the system.

6 0

2 years ago

What is the approximate value of k?

lesya692 [45]

Hello from MrBillDoesMath!

Answer:

5.06

Discussion:

Angle J = 180 - (120 + 40) = 180 - 160 = 20 degrees,

From the law of sines

sin(120)/k = sin(20)/2 =>

sin(120) = k * ( sin(20)/2) ) (multiply both sides by "k")

k = sin(120)/ ( sin(20)/2) (divide both sides by sin(20)/2)

k = (0.866) / ( 0.171) = 5.06

Regards,

MrB

P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!

6 0

2 years ago

A customer purchases 10 m dade co. florida 7.50% g.o. bonds at a 9.50 basis. how much interest will she collect each year? $75 $

crimeas [40]

In the value of bonds, the symbol "M" means "thousands.
Therefore, 10 M = 10,000$

So, the customer bought a coupon with 10,000$ and the expected annual interest is 7.5% of the coupon's value.

Calculating the value of interest is simple, just multiply the interest rate (7.5%) by the original value of the coupon to know how much interest she will collect each year.

Interest collected each year = (7.5 / 100) x 1000 = 750$

5 0

2 years ago