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GuDViN [60]
3 years ago
14

If the square has the same perimeter as the rectangle, find the area of the square.

Mathematics
1 answer:
Serhud [2]3 years ago
8 0
The area would be 12*6
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\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

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\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

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3 years ago
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