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3 years ago

How do you solve the equation k/90-1/9=1/90

Mathematics

2 answers:

Mumz [18]3 years ago

8 0

Answer: 11

Step-by-step explanation:

k/90-1/9=1/90

Multiply left and right side of equation with 90 . You get:

k-10=1

k=10+1

k=11

Mariulka [41]3 years ago

3 0

Answer:

k = 11

Step-by-step explanation:

k/90 - 1/9 = 1/90

k/90 = 1/90 + 1/9

k/90 = 1 + 10/90

k/90 = 11/90

k = 11/90 / 90

k = 11/90 * 90

k = 11

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Aliun [14]

Answer:

Step-by-step explanation:

You have to plug -2 into every x in the function, so:

(-2)^2 - 3 (-2) + 7

4 + 6 + 7

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3 years ago

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kenny6666 [7]

Solving Two- Step Equations:
First you have to add or subtract the number without the variable, x, then divide with the variable with x in it.

1.) -2 - 2=26
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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Cathy is paid at a rate of K7.20 per hour for a basic hour-week of 70 hours. She is paid time-and-a-half for over-time during th

Levart [38]

Answer:

K1310.4

Step-by-step explanation:

Basic pay per hour = K7.20

Overtime pay during the week per hour = 1 1/2 * K7. 20 = K10.8

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Basic hours per week = 70 hours

In a fortnight :

Basic hours = 70 * 2 = 140 hours :

Hence, Overtime during the week = (160 - 140) = 20 hours

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3 years ago

How do you express sin x + cos x in terms of sine only?

frez [133]

Answer:

$\sin x + \sqrt{1-\sin^2x}$

Step-by-step explanation:

Given: sin x + cos x

To change the given trigonometry expression in term of sine only.

Trigonometry identity:-

$\sin^2x+\cos^2x=1$
$\cos x=\sqrt{1-\sin^2x}$

Expression: $\sin x+\cos x$

We get rid of cos x from expression and write as sine form.

Expression: $\sin x + \sqrt{1-\sin^2x}$ $\because \cos x=\sqrt{1-\sin^2x}$

Hence, The final expression is only sine function.

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3 years ago