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Ostrovityanka [42]
3 years ago
14

Answer this by expanding the brackets 20 POINTS!

Mathematics
2 answers:
algol133 years ago
7 0

Answer:

Below

Step-by-step explanation:

(y - 9)(y - 7) = y^2-16y+63

(2y + 2)(y + 1) = 2y^2+4y+2

(2y + 6)(y + 3) =  2y^2+12y+18

(3y + 4)(y + 5) = 3y^2+19y+20

(2y - 7)(y + 2) = 2y^2-3y-14

frez [133]3 years ago
5 0

Answer:

\huge \boxed{y^2  - 16y + 63}

\rule[225]{225}{2}

Step-by-step explanation:

Solving for the first problem:

(y-9)(y-7)

y(y-7)-9(y-7)

y² - 7y - 9y + 63

y² - 16y + 63

\rule[225]{225}{2}

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What are the three types of triangles, based on ANGLES?<br> Draw an example for each one.
artcher [175]

Answer:

Right Triangle, Acute Triangle, and Obtuse Triangle

Step-by-step explanation:

I can't draw it here but the right triangle has a side of 90°.

An acute triangle has a side smaller than 90°.

An obtuse triangle has a side bigger than 90°.

5 0
3 years ago
Which statement defines an annuity?
inna [77]
An investment plan that guarantees payments at regular intervals after retirement

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5 0
4 years ago
Read 2 more answers
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
3 years ago
I need help with 4 and 5
Norma-Jean [14]
4.) The dotted line on the trapezoid is one of the lines. As you can see, to the left of the line is a right triangle. The other line should be drawn on the right side of the trapezoid to section off the other triangle. Now there is a rectangle in the middle with dimensions of 8 cm by 6 cm, and two identical triangles on either side. To find their base length, we can subtract 8 from 12 to get 4. These difference represents the sum of the two triangles' bases. Since the triangles are identical, we can divide 4 in half to get a base of 2 cm for each triangle. Therefore the triangles both have dimensions of 2 cm by 6 cm.

To find the area, we can add together the areas of the triangles and rectangle. We use length times width to find the area of a rectangle, and we use one-half base times height to find the area ofo a triangle.

Rectangle: 8*6 = 48 cm^2

Triangle: 0.5*2*6 = 6 cm^2

So the area of the trapezoid is 48 + 6 + 6 = 60 cm^2
8 0
3 years ago
Pls answer thissssssss
Lerok [7]

Answer:

Area of room = 21 * 16

= 336 m²

Area of Carpet = (21 - 1)* (16-1)

= 20*15

= 300

Area of border = Area of room - Area of carpet

= 336 - 300

<h3>= 36 m².</h3>
4 0
2 years ago
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