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liberstina [14]
3 years ago
10

I Need Help Fast Please

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0
C. 130,90,130.

#01234, the tenths number stays the same
#56789, the tenths number go up 1 number

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Find the unknown coordinate so the line through the points has a given slope.
pashok25 [27]

Answer:

8888888888888888888888 my dude

5 0
3 years ago
01.04) Solve the following for y: −6x + 2y = 8 (5 points) Select one: a. y = −6x + 8 b. y = 6x + 8 c. y = −3x + 4 d. y = 3x + 4
sukhopar [10]
I would recommend leaving y on a side by itself
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5 0
4 years ago
What number does x stand for in this equation?<br><br> -7x + 6=27
AURORKA [14]
⓵ You need to solve the left side first in order to isolate the × and find it’s value :

-7× + 6 = 27
-6 -6
↓

-7× = 21
÷-7 ÷-7

↓

× = -3

If you find it too difficult to divide a number by a negative, just divide 21 by 7 and always remember that when dividing, when the signs are different the answer is negative. So knowing that you could just divide 21 by 7, which is 3, and add a negative sign in front!


I hope this helped, if there’s anything let me know! ☻
3 0
4 years ago
What is 0.08333333333 as a fraction????
katovenus [111]

Answer: So the answer is 083/1000! Hope this helped!!!!!


Step-by-step explanation:

There is not much that can be done to figure out how to write .083 as a fraction, except to literally use what the decimal portion of your number, the .083, means. Since there are 3 digits in 083, the very last digit is the "1000th" decimal place. So we can just say that .083 is the same as 083/1000.

4 0
3 years ago
The label on the car's antifreeze container claims to protect the car between −40°C and 140°C. To covert Celsius temperature to
telo118 [61]

Answer:

-40

Step-by-step explanation:

We must convert the given temperatures from degrees Celsius to degrees Fahrenheit

The formula is:

C=\frac{5}{9}(F-32)

Where C is the temperature in degrees Celsius and F is the temperature in degrees Fahrenheit

Then we must replace the temperature in degrees Celsius and solve the equation for F

C*\frac{9}{5}=(F-32)

F=C*\frac{9}{5}+32

F=(-40)*\frac{9}{5}+32

F=-40\ \°F

F=(140)*\frac{9}{5}+32

F=284\ \°F

The Fahrenheit temperature range in which the antifreeze protects the car is:

-40

5 0
3 years ago
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