Google it. ('>')...................................................
Given:
6 girls
4 boys
Probability of 1 girl being chosen: 1/6
Probability of 1 boy being chosen: 1/4
Probability of another boy being chosen: 1/3
1/6 = 0.17 x 100% = 17%
1/4 = 0.25 x 100% = 25%
1/3 = 0.33 x 100% = 33%
17% + 25% + 33% = 75%
The probability that exactly one girl and two boys will receive awards is 75%.
You can try then by plotting the points in.
The answer is C
Make sure by plotting in the points, lets take (-5,27)
y = 12 -3(-5)
y = 12 + 15
y = 27
27 = 27
This is correct
Lets try (-1,15)
y = 12 -3(-1)
y = 12 + 3
y = 15
15 = 15
This is correct
Lets try (8,-12)
y = 12 -3(8)
y = 12 - 24
y = -12
-12 = -12
This is correct too.
The correct ordered pairs are <span>C(-5,27),(-1,15),(8,-12)</span>
The first penalty they received is three 15 yards so total yards is 3(15 yards)
the second penalty is one 5 yard
the last penalty is half the 34 yard line(34 yard)/2
total change = 3(15 yards) + 5 yrad + (34 yard)/2
= 45 yards + 5 yards + 17 yards= 67yards
Answer:
2x^2-16x+34
Step-by-step explanation:
Since Y is equal to -5
And you substitute -5 in the equation.
You now have -5=2x^2-16x+29
Add 5 to both sides
5-5=2x^-16x+29+5
