Decisions 1 and 3 are both decisions because ________.

Computers and Technology

1 answer:

Hoochie [10]3 years ago

5 0

The Question given is incomplete so from the internet the complete question is as follows:

Health Day Regional Medical center's management team has several decisions to make. They are attempting to sort out what to do first. The decisions are as follows:

1. Determine which patients to be admitted for the next day.

2. Decide weather or not to purchase the only other medical center in their region.

3. Decide which candidates will meet the requirements for the nursing training program.

4. Determine weather the medical center should diversify into more advanced (and substantially more costly ) technologies.

Decisions 1 and 3 are both ____________ decisions because ____________________.

A. Programmed decisions; they are novel and complex

B. Non programmed decisions; they are novel and complex

C. Programmed decisions; they are can be solved using rules and procedures

D. Non programmed decisions; they are novel and complex

E. None of the above is correct

Answer:

Option C is the correct answer.

Decisions 1 and 3 are both Programmed decisions because they can be solved using rules and procedures .

Explanation:

Programmed Decisions can be defined as the ones that are specified and developed for routine problems that are repetitive. These decisions deal with certainty.

Now from the given list of decisions, it is obvious that the decision 1 and 3 are programmed.

Patients that are to be admitted must undergo through the rules and regulations so that a decision may be taken.
Similarly in the case of nurses, proper testing must be conducted and candidates are selected upon this criteria.

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What's the problem with this code ?

Svet_ta [14]

Hi,

I changed your program using some of the concepts you were trying to use. Hopefully you can see how it works:

#include <string>
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>

using namespace std;

int main()
{
short T;
cin >> T;
cin.ignore();

string str[100];

for(int i=0; i<T; i++)
{
getline(cin, str[i]);
}

for (int i = 0; i < T; i++)
{
stringstream ss(str[i]);
string tmp;
vector<string> v;

while (ss >> tmp)
{
// Let's capitalize it before storing in the vector
if (!tmp.empty())
{
transform(begin(tmp), end(tmp), std::begin(tmp), ::tolower);
tmp[0] = toupper(tmp[0]);
}
v.push_back(tmp);
}

if (v.size() == 1)
{
cout << v[0] << endl;
}
else if (v.size() == 2)
{
cout << v[0][0] << ". " << v[1] << endl;
}
else
{
cout << v[0][0] << ". " << v[1][0] << ". " << v[2] << endl;
}
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return 0;
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Answer:

Option A, B & C are correct answers .

Explanation: