If you work 50 weeks/year and 40 hours/week, you will make 16,500 dollars per year if you make 8.25 per hour
Answer:
Primary memory is directly accessible by Processor/CPU. Secondary memory is not directly accessible by the CPU. ... The memory devices used for primary memory are semiconductor memories. The secondary memory devices are magnetic and optical memories
Answer:
There is a considerable difference between a cloud-first strategy and other cloud approaches. The developers of the cloud-first strategy are familiar of every data point that requires backup and synchronization. As a result, a lower assembly layout that is more tolerant of database sync is required. In other words, a cloud-first strategy can easily accommodate new technology.
Cloud-first strategy is the current data management method that was not available a few years ago. Such processes and reliability are inapplicable when transferring application software and data to the cloud. You will have to make sacrifices in terms of load balancing and distributed functionality, which will be limited when using other cloud approaches. And this is where Cloud-first strategy shines, as you will be able to control and use all of the host's functionalities.
Explanation:
A cloud-first strategy is one in which all or most of an organization's structure is moved to a cloud-computing environment. Traditionally, organizations required physical supplies to keep their online data; nowadays, they store it on the cloud, which is fundamentally more useful. Cloud-first organizations, regardless of size or importance, are designed to operate their operations on cloud servers. Rather of transferring the organization's data and services to the cloud, adopt a cloud-first strategy and design the application software from the ground up. Not only does the cloud-first strategy outperform traditional application architectures in terms of performance, but it also provides higher stability.
Programming
It can also be described as Reverse Engineering
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
