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pav-90 [236]
4 years ago
7

To which place value is the number rounded?

Mathematics
1 answer:
Rina8888 [55]4 years ago
5 0

Answer:

c

Step-by-step explanation:  3 is not bigger than 9 so it can't bump it up so it stays like that.

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If an object has a mass of 15 g and a volume of 3 mL what is its density
Annette [7]

Answer:

Given the mass of the object = 15g

Given the volume of the object = 3 mL

Density = ?

Step-by-step explanation:

We have two values of an object that is mass of the object and volume of the object. Now we are required to find the Density of the object. In order to find the density of the object, we have to divide the given mass with the given volume. Below is the calculation of the density.

Density = Mass / Volume

Density = 15g / 3 mL

Density = 5 g/ml

7 0
3 years ago
Cos(0.5)+cos(0.5+2(3.14159265))+cos(0.5+4(3.14159265))
aleksandr82 [10.1K]

Answer:

2.63274768567

Step-by-step explanation:

First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.

2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).

So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567

I hope this helps! :)

7 0
3 years ago
Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for
nevsk [136]

Answer:168

Step-by-step explanation:   First you do 82 times 3.75 which is 307.50. Then you do 2071.5 - 307.5 = 1764 Then you do 1764 divided by 10.50 which is 168

9 0
3 years ago
Read 2 more answers
What is 11/2 divided by 3/4
madam [21]

Answer:

2 and 14/15

Step-by-step explanation:

7 0
3 years ago
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
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