Answer:
![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
![\sqrt[4]{\sqrt[3]{2^2}} =((2^2)^\frac{1}{3})^\frac{1}{4}\\\\=(2^2)^\frac{1}{12}\\\\=2^\frac{2}{12}\\\\=2^\frac{1}{6}\\\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Csqrt%5B3%5D%7B2%5E2%7D%7D%20%3D%28%282%5E2%29%5E%5Cfrac%7B1%7D%7B3%7D%29%5E%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%3D%282%5E2%29%5E%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B2%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)
Answer:
81,000,000
Step-by-step explanation:
(3²)² × (10³)²
(9)² × (1000)²
81 × 1000000
81,000,000
Answer:
Yes
Step-by-step explanation:
Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.
When both machines work for 20 minutes
Machine A would produce =
widget and
Machine B would produce =
widgets
So we can say that Machine A would produce more widgets than Machine N at that time.
Answer is Yes
The answer id 12 meters.divide -2x^2+20x+48 by 2 to get x alone and then umbrella