[-4 6 3 -4] [2 3 1.5 T]

Sove -5x + 3 = 2x - 1

DiKsa [7]

Answer:

4/7

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.

ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: $u_{x x}+u_{y y}=0$

We must determine whether a given function is the solution to a given Laplace equation.
If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) $u=e^{-x} \cos y-e^{-y} \cos x$

Differentiate with respect to x as follows:

$u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x$

Differentiate with respect to y as follows:

$u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x$

Supplement the values in the given Laplace equation.

$e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0$

The given function in this case is the solution to the given Laplace equation.

(2) $u=\sin x \cosh y+\cos x \sinh y$

Differentiate with respect to x as follows:

$u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y$

Differentiate with respect to y as follows:

$u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y$

Substitute the values to obtain:

$-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0$
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

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The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

6 0

2 years ago

Help answer question 2

Effectus [21]

All you have to do is add them. So using the number line by looking at the -3 mark and find the -5 mark. Then you just add them together and you have your answer of -8!!

7 0

3 years ago

30 treadmills to 36 elliptical machines the ratio in simplest form

Goshia [24]

30 treadmills : 36 ellipticals
this could be written in a few ways, but i am going to write it as a fraction. since treadmills come first, you put 30/36.

now that you have your fraction you have to find the GCF (greatest common factor) of the two numbers. the GCF is 6, so you have to divide 30 treadmills by 6, and 36 ellipticals by 6.
30/6=5
36/6=6

5/6 or 5:6 is the simplified ratio of treadmills to ellipticals

comment for any questions!!

4 0

4 years ago

When a teacher counted her student in group 4. There were 2 students left over.When she counted them in groups of 5.She had I st

VARVARA [1.3K]

Answer:

Step-by-step explanation:

Number of students in her class = x students

x is 2 more than a multiple of 4

This means x is an even number because multiples of 4 are even and adding 2 does not change its parity.

X is also 1 more than a multiple of 5. And we know x is and even number it has to be a multiple of 5 ending in 5, not 0. So 5 + 1 is 6.

All multiples of 4 ending in six are 16, 36, 56 ..... and so on

Since there are 15 girls and lower no of boys we need to find out which number of boys are there in 16, 36, 56.

16- 15 = 1

36 - 15 = 21

And 21 is more than 15 therefore the answer is 16 students. 15 girls and 1 boy.

7 0

4 years ago