Answer:
we have only two or three acute angles in a triangle. so ima say at least 1
Step-by-step explanation:
I'm assuming your answers are listed as 1 through 4, not decimals.
You simply take 12 - 8 = 4, but ten min. less than that, so 3 hr, 50 min. then add 3 hr 45 min, totaling 7 hr 35 min. , which is closest to 7 and 1/2 hours, the second option.
Answer:
f(g(x)) = x
Explanation:
In order to prove that one function is the inverse of the other, all you have to do is substitute in the main function with the inverse one and solve. If the result is x, then it is verified that one function is the inverse of the other.
Now for the given functions we have:
<span>f(x) =5x-25
</span><span>g(x) = (1/5)x+5
We want to prove that g(x) is the inverse of f(x).
Substitute in the above formula and compute the result as follows:
f(g(x)) = 5(</span>(1/5)x+5) - 25
= x + 25 - 25
= x
The final result is "x", therefore, it is verified that g(x) is the inverse of f(x)
Hope this helps :)
Answer:

Step-by-step explanation:
We have,
Radius of the circle is 12 cm
Arc length, l = 21 cm
It is required to find the central angle of the circle. The formula for the length of an arc of a circle is :

is central angle

So, the angle at the centre of the circle is
.
Answer:
b, e
Step-by-step explanation:
a, b) ordinarily, we claim the variable on the vertical axis is a function of the variable on the horizontal axis. By that claim, <em>temperature is a function of time</em>.
If the graph passed the horizontal line test (a horizontal line intersects in one place), then we could also say time is a function of temperature. The graph does not pass that test, so we cannot make that claim.
c) The graph has negative slope between 4:00 and 5:00. Temperature is decreasing in that interval, not increasing.
d) The graph has two intervals in which it is horizontal: 5:00-9:00 and 11:00-12:00. In those intervals it is neither increasing nor decreasing.
e) The graph shows a minimum in the interval 11:00-12:00. <em>The lowest temperature first occurs at 11:00</em>.