1. A relation is a set from x to a set y is called a function if each element of c is related to exactly one element in y. That is,given an element c in c, there is only one element in y that x is related to.
2. You can set up the relation as a table of ordered pairs. Then, text to see if each element in the domain is matched with exactly one element in the range . if so you have a function
3. The domain is the set of all possible x-values which will make the function "work" and will output real y- values .When finding the domain , remember :the denominator (bottom) of a fraction cannot be zero .
4.
Katework+jeanwork=6
work alone
Katework=-5+Jeanwork
ad 5 to both sides
Katework+5=jeanwork
subsitute 5+katework for jeanwork
5+katework+kateworkwork=6
subtract 5 from both sides
2katework=1
divide both sides by 2
katework=0.5days
equation would be
jeanwork+katework=6 and
katework=jeanwork-5 are the equations
Answer:
3) Midpoint is (-4,0.5)
Option A is correct.
4) Midpoint is (2.5,0)
Option B is correct.
5) The factors are (x+4)(x-7)
Option C is correct.
6) The factors are (x+4)(x+2)
Option A is correct.
Step-by-step explanation:
Question 3
Find midpoint of the following:
(2,-7), (-10,8)
The formula used to find midpoint is: 
We have 
Putting values and finding midpoint

So, Midpoint is (-4,0.5)
Option A is correct.
Question 4
Find midpoint of the following:
(2,-10), (3,10)
The formula used to find midpoint is: 
We have 
Putting values and finding midpoint

So, Midpoint is (2.5,0)
Option B is correct.
Question 5
Factor each completely

We will break the middle term and find factors

So, the factors are (x+4)(x-7)
Option C is correct.
Question 6
Factor each completely

We will break the middle term and find factors

So, the factors are (x+4)(x+2)
Option A is correct.
Answer:
Given: Quadrilateral P QR S is a rectangle.
To prove :PR= Q S
Construction : Join PR and Q S.
Proof: In Rectangle PQRS, and
→ taking two triangles PSR and Δ QRS
1. PS = Q R
2. ∠ PS R = ∠ Q RS [Each being 90°]
3. S R is common.
→ ΔP SR ≅ Δ Q RS → [Side-Angle-Side Congruency]
∴ PR =Q S [ corresponding part of congruent triangles ]
Hence proved.
Answer:
-37
Step-by-step explanation:
It would be greatly appreciated if you gave me brainlest