Solve the proportion -- 33/6 = 55/z

nikklg [1K]

To figure out the cost per cookie, divide $2.49 by 3. The cost per 1 cookie (column 1) would be .83 cents.

To figure out the cost of 20 cookies, multiply 20 x .83 cents. The answer is 20 cookies would cost $16.60

To figure out how many cookies would cost $145,25, divide $145.25 by .83 cents. The answer is 175 cookies would cost $145.25

4 0

3 years ago

Find the dimensions of the rectangular box with largest volume if the total surface area is given as 64cm^2

motikmotik

Let x =lenght, y = width, and z =height
The volume of the box is equal to V = xyz 
Subject to the surface area 
S = 2xy + 2xz + 2yz = 64 
= 2(xy + xz + yz) 
= 2[xy + x(64/xy) + y(64/xy)] 
S(x,y)= 2(xy + 64/y + 64/x) 
Then 
Mx(x, y) = y = 64/x^2 
My(x, y) = x = 64/y^2 
y^2 = 64/x 
(64/x^2)^2 = 64 
4096/x^4 = 64/x 
x^3 = 4096/64 
x^3 = 64 
x = 4 
y = 64/x^2 
y = 4 
z= 64/yx 
z= 64/16 
z = 4 

Therefor the dimensions are cube 4.

6 0

4 years ago

Rene has a coupon for $3.25off a package of name-brand cookies that normally cost $7.89. The store-brand cookies cost $5.58. How

jeka94

$10.22 this is the answer for you..............

5 0

3 years ago

The distribution of the number of viewers for the American Idol TV broadcasts follows the normal distribution of a mean of 29 mi

e-lub [12.9K]

Answer:

a) $P(30$

And we can find this probability on this way:

$P(0.2$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(0.2$

b) $P(X\geq 23)=P(\frac{X-\mu}{\sigma}\geq \frac{23-\mu}{\sigma})=P(Z\geq \frac{23-29}{5})=P(Z\geq -1.2)$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(Z\geq -1.2)=1-P(Z$

c) $P(X> 40)=P(\frac{X-\mu}{\sigma}> \frac{40-\mu}{\sigma})=P(Z\geq \frac{40-29}{5})=P(Z> 2.2)$

And in order to find the probabilitiy we can use tables for the normal standard distribution, excel or a calculator.

$P(Z>2.2)=1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the number of viewers for the American Idol TV of a population, and for this case we know the distribution for X is given by:

$X \sim N(29,5)$

Where $\mu=29$ and $\sigma=5$ with the values on this case representing millions

We are interested on this probability :

$P(30$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(30$

And we can find this probability on this way:

$P(0.2$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(0.2$

Part b

We are interested on this probability :

$P(X\geq 23)$

$P(X\geq 23)=P(\frac{X-\mu}{\sigma}\geq \frac{23-\mu}{\sigma})=P(Z\geq \frac{23-29}{5})=P(Z\geq -1.2)$

And in order to find the probabilitiy we can use tables for the normal standard distribution, excel or a calculator.

$P(Z\geq -1.2)=1-P(Z$

Part c

We are interested on this probability :

$P(X> 40)$

$P(X> 40)=P(\frac{X-\mu}{\sigma}> \frac{40-\mu}{\sigma})=P(Z\geq \frac{40-29}{5})=P(Z> 2.2)$

And in order to find the probabilitiy we can use tables for the normal standard distribution, excel or a calculator.

$P(Z>2.2)=1-P(Z$

7 0

4 years ago

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

agasfer [191]

Answer:

WOW that's tough to read all squished together!!!

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as 7 centimeters. The hypotenuse is labeled as 13 centimeters.

Jayden's Work

Sheridan's Work

a2 + b2 = c2

a2 + b2 = c

272 + 132 = c272 + b2 = 132

49 + 169 = c

249 + b2 = 169

218 = c2b2 = 120

Square root 218 equals square root c squared.

Square root b squared equals

square root 120.

14.76 ≈ cb ≈

10.95Is either of them correct?

***************************************************

In a right triangle

hypotenuse^2 = leg1 ^2 + leg2^2

13^2 = 7^2 + leg2^2

leg2^2 = 120

leg 2 = 10.9544511501

Basically, whoever said 10.95 is correct.

Step-by-step explanation:

3 0

4 years ago