image of solution attached below
is the area of a semicircle with a diameter of 2x greater than, less than, or equal the area of a circle with a radius of x
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Answer:
<h2>GRAPH III</h2>Step-by-step explanation:
Look at the picture.
We have
y = x² - 4 → move the graph of x² 4 units down (the vertex is (0, -4))
x + y + 2 = 0 <em>subtracy x and 2 from both sides</em>
y = -x - 2 → move the graph of -x 2 units down (the y-intercept os -2)
Only graph III and IV meets these conditions.
The solution is the points of intersection of the graphs.
Therefore your answer is GRAPH III
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