The total number of students enrolled in MATH 123 this semester is 5,780. If it
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We need to graph this equation:
Its solutions are the points through which it graph passes. Since it's a linear equation its graph is a straight line and we only need two of its points to draw it. But before graphing let's re-write the equation. We can substract 16x from both sides:
And we divide both sides by 2:
So now with this equation if we pick two random x values we'll get their corresponding y values. This way we'll find two points that are part of the graph which is the line that passes through both. We can begin with x=0:
So the first point is (0,150). Then we can take x=10 and we get:
So the second point is (10,70). Then the graph is the line that passes through points (0,150) and (10,70). In order to represent it