Answers:
Option 1)
6a + 8s = 102
14a + 4s = 150
each adult ticket costs 9 dollars
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Explanation:
6 adult tickets and 8 student tickets bring in $102, so that means 6a+8s = 102
14 adult tickets and 4 students tickets bring in $150, so 14a+4s = 150
The system of equations is

If we multiply both sides of the second equation by -2, we get this updated system

Add the equations straight down
6a+(-28a) = -22a
8s+(-8s) = 0s = 0 ... the 's' terms go away
102+(-300) = -198
So we end up with the equation -22a = -198 and that solves to a = 9 after dividing both sides by -22.
Each adult ticket costs $9
If you want the value of s, then
6a+8s = 102
6(9)+8s = 102
54 + 8s = 102
8s = 102-54
8s = 48
s = 48/8
s = 6
Meaning each student ticket costs $6
Or you could use the other equation
14a+4s = 150
14(9)+4s = 150
126+4s = 150
4s = 150-126
4s = 24
s = 24/4
s = 6
We get the same value of s
I mean, you took 42 so.. 42. but if you're asking how many are left.. then 285
Distribute the 5 to each of the numbers so you should get 5x+5+5x+5+5x+35. after this you should combine like terms, all of the 5’s & the 35 and 5x’s. you should have 15x+45. then you divide 45 by the 15 and you should get x=3
The following information will help us with this problem:
![\sqrt[m]{x^n} = x^{\frac{n}{m}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5En%7D%20%3D%20x%5E%7B%5Cfrac%7Bn%7D%7Bm%7D)
When we use that information in the context of this problem, we can find:
![\sqrt[4]{15^7} = 15^{\frac{7}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B15%5E7%7D%20%3D%2015%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D)
Thus, a = 15, b = 7, and c = 4.
Answer: Multiply the radius,r, by 2. Divide the angle measure, x, by 4.