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Allisa [31]
4 years ago
6

(Please show all work) 1). Solve x- y/7=2 for y

Mathematics
1 answer:
Nat2105 [25]4 years ago
6 0

1. You can solve this problem like you would any other equation:

x-(y/7)=2

<em>*Subtract x from both sides*</em>

-y/7=2-x

<em>*Multiply both sides by 7*</em>

-y=14-7x

<em>*Divide both sides by -1*</em>

y=7x-14

2. This is the same as finding the slope.  The equation for slope is (y2-y1)/(x1-x2).

(53-8)/(10-1)

45/9

5

3. The general formula for a linear equation is y=mx+b, where m is the slope and b is the y-intercept.  The slope will remain the same because the lines are parallel.  To solve for b, plug in the given coordinates:

4=0.5(6)+b

4=3+b

<em>*Subtract 3 from both sides*</em>

1=b

The equation is y=1/2+1

Hope this helps!!

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A car travels 76 km in 47 minutes.
Mumz [18]

Answer:

97km/h to 1dp

Step-by-step explanation:

47mins is 0.783 of an hour

76km/0.783 = 97.0212km/h

3 0
3 years ago
To determine whether 30 horses can be put into 7 stalls; so that in every stall there may be, either a single horse, or an odd n
algol [13]

Answer: No solutions

If i put any combo of horses of single or odd, always an even number at last stall.

3 0
3 years ago
Which equation could you use to solve for x in the proportion 4/5=9/x?
andre [41]

Answer:

11.25

Step-by-step explanation:

Step 1:

4/5 = 9/x   Proportion

Step 2:

4x = 45    Multiply

Step 3:

45 ÷ 4     Divide

Answer:

x = 11.25

Hope This Helps :)

6 0
4 years ago
Read 2 more answers
Which expressions represent the difference of exactly two expressions? Choose 3 answers: Choose 3 answers: (Choice
Ket [755]

Solution

To find out which expressions represent the difference of exactly

two expressions

a) 6(x+7) - 2

This can be simplified as

6x + 42 - 2

6x + 40

Clearly this does not represent difference of the two

expressions .


b) -2j

Clearly this represents a single expression , this does not represent

a difference of 2 expression .


c) 4f - 2g

Here we have 2 different expressions 4f and 2g

Difference of these 2 expressions are 4f - 2g

Hence , this option represent difference of exactly two

expression


d) 3xyz - 10

3xtz - 10 represnts a single expression

Here we have a single expression

Therefore it does not represent difference of exactly 2

expression .

3 0
3 years ago
A Ferris wheel is 20 meters in diameter and boarded from a platform that is 2 meters above the ground. The six o'clock position
pantera1 [17]

Answer:

233.48s  

3.84 min

Step-by-step explanation:

In order to solve this problem, we can start by drawing what the situation looks like. See attached picture.

We can model this situation by making use of a trigonometric function. Trigonometric functions have the following shape:

y=A cos(\omega t+\phi)+C

where:

A= amplitude =-20m because the model starts at the lowest point of the trajectory.

f= the function to use, in this case we'll use cos, since it starts at the lowest point of the trajectory.

t= time

\omega= angular speed.

in this case:

\omega=\frac{2\pi}{T}

where T is the period, in this case 6 min or

6min(\frac{60s}{1min})=360s

so:

\omega=\frac{2\pi}{360}

\omega = \frac{\pi}{160}

and

\phi= phase angle

C= vertical shift

in this case our vertical shift will be:

2m+20m=22m

in this case the phase angle is 0 because we are starting at the lowest point of the trajectory. So the equation for the ferris wheel will be:

y=-20 cos(\frac{\pi}{180}t)+22

Once we got this equation, we can figure out on what times the passenger will be higher than 13 m, so we build the following inequality:

-20 cos(\frac{\pi}{180}t)+22>13

so we can solve this inequality, we can start by turning it into an equation we can solve for t:

-20 cos(\frac{\pi}{180}t)+22=13

and solve it:

-20 cos(\frac{\pi}{180}t)=13-22

-20 cos(\frac{\pi}{180}t)=-9

cos(\frac{\pi}{180}t)=\frac{9}{20}

and we can take the inverse of cos to get:

\frac{\pi}{180}t=cos^{-1}(\frac{9}{20})

which yields two possible answers: (see attached picture)

so

\frac{\pi}{180}t=1.104 or \frac{\pi}{180}t=5.179

so we can solve the two equations. Let's start with the first one:

\frac{\pi}{180}t=1.104

t =1.104(\frac{180}{\pi})

t=63.25s

and the second one:

\frac{\pi}{180}t=5.179

t=5.179(\frac{180}{\pi})

t=296.73s

so now we can build our possible intervals we can use to test the inequality:

[0, 63.25]  for a test value of 1

[63.25,296.73] for a test value of 70

[296.73, 360] for a test value of 300

let's test the first interval:

[0, 63.25]  for a test value of 1

-20 cos(\frac{\pi}{180}(1))+22>13

2>13 this is false

let's now test the second interval:

[63.25,296.73] for a test value of 70

-20 cos(\frac{\pi}{180}(70))+22>13

15.16>13 this is true

and finally the third interval:

[296.73, 360] for a test value of 300

-20 cos(\frac{\pi}{180}(300))+22>13

12>13 this is false.

We only got one true outcome which belonged to the second interval:

[63.25,296.73]

so the total time spent above a height of 13m will be:

196.73-63.25=233.48s

which is the same as:

233.48(\frac{1min}{60s})=3.84 min

see attached picture for the graph of the situation. The shaded region represents the region where the passenger will be higher than 13 m.

3 0
3 years ago
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