I Believe the answer would be (4, 270)
Part 1We are given
. This can be rewritten as
.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
The values of x are
Part 2Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a
quadratic function. Part 3.The first equation is
.
The second equation is
.
We have
Factoring, we have
Equating both factors to zero.
When the value of x is 6, the value of y is
When the value of x is -3, the value of y is
Therefore, the solutions are (6,38) or (-3,11)
Answer:
5 hours
Step-by-step explanation:
276/12= 23
115/23= 5
Answer:
LOL I NEED POINTS SORRY NOT SORRY
Step-by-step explanation:
Answer:
=4m^2−11m+6
Step-by-step explanation:
Given algebraic expression:
(m-2)(m•2+2m-3)
To:
Simplify
Solution:
(m−2)(m(2)+2m−3)
=(m)(m(2))+(m)(2m)+(m)(−3)+(−2)(m(2))+(−2)(2m)+(−2(−3)
=2m^2+2m^2−3m−4m−4m+6
=4m^2−11m+6