Answer:
If the time passed is only 3 months, then it is $2040
Step-by-step explanation:
We can use the quarterly compounded interest equation for this problem: P(1 + r/n)^nt
Step 1: Find out how much 3 months is in a year
<em>In this case, 3/12 which is 1/4</em>
Step 2: Plug in known variables into equation
2000[1 + (0.08)/4)]^[(4)(1/4)]
Step 3: Solve/Plug in calc
You will get $2040
If the time passed in the problem is 1 year, then we can be able to solve how much money he earned per quarter. However, since only 3 months have elapsed, then he has only earned $2040.
If the cost increases $0.90 every three years , then the cost increases $0.30 per year. the slope will be 0.3/1 or just 0.3
Answer: Lower right corner
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Explanation:
The information that the temperature rises 3 degrees per hour will tell us the slope here. The slope is rise/run = 3/1 = 3. Each time we move up 3 on the y axis, we move 1 spot to the right.
As you can see in the bottom right hand corner graph, we start off at a temperature of 20 degrees. This is the point (x,y) = (0,20)
Then one hour later (x = 1), the temperature y bumps up to y = 23. Another hour passes by (x = 2) and y becomes y = 26. And so on.
8 * 5 = 40
40 * 4 = 160
160 * 12 = 1,920
Answer: $1,920
