A cyclist travels 64 km during the first 4 hours. Then the cyclist travels 26 km during the two hours. What is the
1 answer:
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Answer:
a)
H₀: ρ₁ ≤ ρ₂
H₁: ρ₁ > ρ₂
b)
Z= ≈ N(0;1)
c)
p-value < .00001
d)
Reject the null hypothesis.
The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.
Step-by-step explanation:
Hello!
The objective is to test if the population proportion of vinyl gloves that leak viruses (population 1) is greater then the population proportion of latex gloves that leak viruses (population 2).
Sample 1 (Vinyl)
n₁= 225
Sample proportion 'ρ₁= 0.60
Sample 2 (Latex)
n₂= 225
Sample proportion 'ρ₂= 0.09
Pooled proportion: 'ρ= (x₁+x₂)/(n₁+n₂)= ( 'ρ₁ + 'ρ₂)/2= (0.60 + 0.09)/2= 0.345 ≅0.35
The hypothesis is:
H₀: ρ₁ ≤ ρ₂
H₁: ρ₁ > ρ₂
α: 0.05
The statistic to use is a pooled Z
Z= ≈ N(0;1)
The critical region is one-tailed to the right (positive), the critical value is:
If Z ≥ 1.64, you will reject the null hypothesis.
If Z < 1.64, you will not reject the null hypothesis.
Z= = 11.34
Since the calculated Z- value is greater than the critical value, the decision is to reject the null hypothesis. The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.
P-value approach:
p-value < .00001
If you compare with the level of signification, you reach the same decision.
I hope it helps!
Answer:
Rate of change of money in Michael's account will be $20 per week.
Step-by-step explanation:
If we draw a graph for the duration of investment on x-axis and amount in the account on y-axis, ordered pairs for both the conditions will be,
After 6 weeks, amount in the account = $140
Ordered pair : (6, 140)
After 12 weeks, amount in the account = $260
Ordered pair : (12, 260)
Rate of change in hi account per week =
=
=
= $20 per week
Therefore, rate of change of money in Michael's account will be $20 per week.