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2 years ago

5

A box contains $7.05 in nickels, dimes, and quarters. There are 42 coins in all, and the sum of the numbers of nickels and dimes

is 2 less than the number of quarters. How many coins of each kind are there?

1 answer:

german2 years ago

3 0

I BELIEVE that there are 22 quarters, 13 dimes, and 7 nickels I’m super super sorry if wrong

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3 years ago

3) The length of JM is 9x + 6 units, the length of JK is

Vlada [557]

Answer:

$JM = 60 units$

Step-by-step explanation:

Given:

$JM = 9x + 6$

$JK = 5x$

$KM = 3x + 12$

$JK + KM = JM$ (segment addition postulate)

$(5x) + (3x + 12) = (9x + 6)$ (substitution)

Solve for x

$5x + 3x + 12 = 9x + 6$

Collect like terms

$5x + 3x - 9x = -12 + 6$

$-x = -6$

Divide both sides by -1

$x = 6$

$JM = 9x + 6$

Plug in the value of x

$JM = 9(6) + 6$

$JM = 54 + 6$

$JM = 60 units$

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3 years ago