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Ann [662]
3 years ago
7

Please identify the error 8 - (-2) = -8 +2 = -6

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0
False bc

8+2=-8+2
8=-8
But if it was solve:
8-(-2) the answer is:
8+2=10
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ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
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Answer:

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Step-by-step explanation:

Given:

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Solution:

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Distance d = \sqrt{(x_2-x_1)^2 +( y_2-y_1)^2

Step 1: Finding the length of  EF

By using distance formula,

EF = \sqrt{(-7 - 0)^2 + (4-0)^2}

EF = \sqrt{(49) + (16)}

EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\

Step 2: Finding the length of  FG

By using distance formula,

FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

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