person A 105 miles to the west and then drive 56 miles to the south. how far is person A starting location

Mathematics

1 answer:

KengaRu [80]3 years ago

4 0

Dirt is germ that is gas state carbon which is highly flammable

You might be interested in

50 POINTS! PLEASE ASAP, BRAINLIST

Aleks04 [339]

Answer:

Quadratic equations are similar to exponential equations by having a curve in the graph. Algebraically, linear functions are polynomial functions with a highest exponent of one, exponential functions have a variable in the exponent, and quadratic functions are polynomial functions with a highest exponent of two.

6 0

3 years ago

At the end of the sale, 22 crossbody purses were sold at $15 each, 34 wristlets priced at $12 were sold, 96 satchels marked at $

Brrunno [24]

Answer:

Average: 26.223529411764706 (Please round to the place value necessary since it does not say in the question.)

Step-by-step explanation:

We first find the number of items sold: 170

Then we find the total cost: 4458

We then divide 4458 by 170

We end up with the answer 26.223529411764706. (Please round to the place value necessary since it does not say in the question.)

5 0

2 years ago

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago

How do you write the equation of a line and stop intercept form from that passes through the point -3, 5

mr_godi [17]

Y=2/3x -5/2

Slope is equal to the parallel line (2/3)
Find y intercept by setting y and x equal the given coordinates and solve.

8 0

3 years ago

Evaluate the expression when x=-3.<br> x^2+5x=-4

Neporo4naja [7]

$(-3)^{2} + 5(-3) = - 4\\9 - 15 = - 4\\-6 \neq -4$

This is not possible, as -6 is not equal to -4.

3 0

3 years ago